Ignoring ctrl-c

I'm trying to write a shell and I'm at the point where I want to ignore ctrl-c.

I currently have my program ignoring SIGINT and printing a new line when the signal comes, but how can I prevent the ^C from being printed?

When pressing ctrl-c, here is what I get:

myshell>^C
myshell>^C
myshell>^C

but I want:

myshell>
myshell>
myshell>

Here is my code relevant to ctrl-c:

extern "C" void disp( int sig )
{
    printf("\n");
}

main()
{
    sigset( SIGINT, disp );
    while(1)
    {
        Command::_currentCommand.prompt();
        yyparse();
    }
}

From stackoverflow

• Try printing the backspace character, aka \b ?

• It's the terminal that does echo that thing. You have to tell it to stop doing that. My manpage of stty says

  * [-]ctlecho
         echo control characters in hat notation (`^c')
  

  running strace stty ctlecho shows

  ioctl(0, SNDCTL_TMR_TIMEBASE or TCGETS, {B38400 opost isig icanon echo ...}) = 0
  ioctl(0, SNDCTL_TMR_STOP or TCSETSW, {B38400 opost isig icanon echo ...}) = 0
  ioctl(0, SNDCTL_TMR_TIMEBASE or TCGETS, {B38400 opost isig icanon echo ...}) = 0
  

  So running ioctl with the right parameters could switch that control echo off. Look into man termios for a convenient interface to those. It's easy to use them

  #include <termios.h>
  #include <unistd.h>
  #include <stdio.h>
  
  void setup_term(void) {
      struct termios t;
      tcgetattr(0, &t);
      t.c_lflag &= ~ECHOCTL;
      tcsetattr(0, TCSANOW, &t);
  }
  
  int main() {
      setup_term();
      getchar();
  }
  

  Alternatively, you can consider using GNU readline to read a line of input. As far as i know, it has options to stop the terminal doing that sort of stuff.